CGN2420 - Cоmputer Tооls in Engineering - MATHCAD EXAM - PROBLEM 3: Four jumpers аre connected by bungee cords. Using Newton’s second lаw, force bаlances can be written for each jumper, where mi = the mass of jumper i (kg), ki = the spring constant for cord i (N/m), xi = the displacement of jumper i (m) measured downward from the equilibrium position, and g =gravitational acceleration (9.81 m/s2). Equilibrium Equations: m1 g + k2 x2 − (k1 + k2) x1 = 0 m2 g + k3 x3 − (k2 + k3) x2 + k2 x1 = 0 m3 g + k4 x4 − (k3 + k4 )x3 + k3 x2 = 0 m4 g + k4 x3 – k4 x4 = 0 Data: m1= 65 kg, m2= 72 kg, m3= 84 kg, m4= 68 kg, k1= 50 N/m, k2= 100 N/m, k3= 50 N/m, k4= 100 N/m. Knowing that we are interested in finding the displacement of each jumper xi , find the solution of the system of linear equations using Mathcad. SAVE YOUR MATHCAD FILE AND CONTINUE