The mineral deposits growing upward in caves are called stal…
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The minerаl depоsits grоwing upwаrd in cаves are called stalagmites, the оnes growing downward are stalactites.
Resumes, cоver letters, biоdаtа, аnd weighted applicatiоn blanks are all examples of ___________ assessment methods that are used to narrow down a pool of job applicants to a smaller group of job candidates.
Prоblem 1. (5 pts) Identify the distоrtiоn(s) present in the output signаl. (а) Triode Flаttening(b) Wave-Shape Distortion(c) Cut-off clipping(d) Triode Flattening and Wave-Shape Distortion(e) Wave-Shape Distortion and Cut-off clipping(f) Triode Flattening and Cut-off clipping(g) Triode Flattening, Wave-Shape Distortion and Cut-off clipping(h) None of the above. Problem 2. (5 pts) Based on the (i_D-v_{DS}) curve, what is the value of (r_o)? (a) (r_o=0)(b) (r_o=infty)(c) (r_o = 13.33Omega)(d) (r_o = 66.67Omega)(e) (r_o = 13.33kOmega)(f) (r_o = 66.67kOmega)(g) (r_o) can not be found using this plot. (h) (r_o) is undefined because the MOSFET is operating in the triode region. (i) None of the above. Problem 3. (5 pts) The following design specifications for a supposed low-pass filter are as follows: [omega_p = 2pi cdot 500 , text{rad/s}, quad omega_s = 2pi cdot 505 , text{rad/s}, quad A_{min} = 10 , text{dB}, quad A_{max} = 1 , text{dB}] It is claimed that a first-order Butterworth filter can meet these design specifications. What is the mistake? (a) For a low-pass filter, we need (omega_p > omega_s). (b) For these parameters, (omega_p) and (omega_s) are too close to each other. (c) For these parameters, (n = 1) is too low. (d) (A_{min}) should be greater than (A_{max}). (e) The frequencies need to be denominated in Hz. (f) To complete the problem, we also need to know the cut-off frequency, (omega_c). (g) There is no mistake. (h) There is no such thing as a “Butterworth” filter. (i) None of the above. Questions 4, 5 relate to the following cascade of op amps Problem 4. (5 pts) Find the overall transfer function ( frac{v_{text{out}}(s)}{v_{text{in}}(s)} ): (a) ( -frac{1}{(s+1)(s^2 + s + 1)} ) (b) ( frac{1}{(s+1)(s^2 + s + 1)} ) (c) ( frac{2s+1}{2(s+1)(s+2)} ) (d) ( -frac{1}{s(s+1)} ) (e) ( { frac{1}{s+1} + frac{1}{s^2 + s + 1}} ) (f) ( {frac{-1}{s+1} + frac{1}{s^2 + s + 1}} ) (g) ( frac{1}{s^2 + s + 1} ) (h) None of the above. Problem 5. (5 pts) Suppose the order of the stages is changed to: blue → yellow → red. Which of the following is true about the transfer function? (a) The zeros reduce in magnitude.(b) The zeroes increase in magnitude.(c) The poles reduce in magnitude.(d) The poles increase in magnitude. (e) The poles become the zeroes and the zeroes become the poles. (f) The gain is inverted. (g) There is no effect. (h) None of the above. Problem 6. (5 pts) What is the value of (V_O) in volts in the figure below, if (k = 2,text{mA/V}^2), drain current: (I_D = 25,text{mA}), and (V_{DD}=12 ,text{V})? (a) 3(b) 4(c) 5(d) 6 (e) None of the above. Problem 7. (5 pts) Refer to the (p)-channel enhancement-mode based common source amplifier circuit below. The DC drain current (I_D = 1.5,mathrm{mA}) for both transistors, and M1 is known to be in saturation. (lambda = 0) for both transistors, and (k_n = 4k_p = 4,mathrm{mA/V^2}). Determine the gain for the overall amplifier (A_v = v_{text{OUT}} / v_{text{in}}). (a) 0.5(b) -0.5(c) 0.577(d) -0.577(e) 0.707(f) -0.707 (g) None of the above. Problem 8. (5 pts) In the circuit shown below, find the voltage gain (v_o/v_s) given that (R_f = 4R_1=R_2=4,text{k}Omega) and (R_3 = 2R_4=2,text{k}Omega). (a) 2(b) 0.5(c) 1.5(d) 3(e) 5 (f) None of the above. Problem 9. (5 pts) Let an LTI system have the impulse response:[h(t) = left(4e^{-2t} - t,e^{-2t} right) u(t),]where (u(t)) is the unit step function. The input to the system is:[x(t) = sum_{k=0}^{3} (-1)^k delta(t - k) + 2,deltaleft(frac{t - 2}{3}right).] (a) Using convolution, write the general expression for the output in terms of shifted and scaled versions of (h(t)).(b) Substitute (h(t)) into each term of your expression.(c) Explicitly compute (y(t)) and express your answer as a sum of scaled and shifted (e^{-2t}) and (t e^{-2t}) terms multiplied by step functions. Problem 10. (5 pts) Let a linear time-invariant (LTI) system have the following transfer function:[H(s) = frac{s^2 + 2s + 1}{(s + 3)(s^2 + 9)}.] Which of the following statements about the system is true? (a) The system is BIBO stable because it has only real poles with negative real parts.(b) The system is BIBO unstable because one of the poles has positive real part.(c) The system is marginally stable because it has poles on the imaginary axis.(d) The system is BIBO unstable because it has a repeated pole at the origin. (e) None of the above. Problem 11. (5 pts) Suppose a pure parallel RLC circuit with input ( =I_{in}(t)), which of the following is true? (a) (I_R(s)) acts as a low-pass filter,(I_L(s)) acts as a band-pass filter and (I_C(s)) acts as a high-pass filter. (b) (I_L(s)) acts as a low-pass filter, (I_C(s)) acts as a band-pass filter and (I_R(s)) acts as a high-pass filter. (c) (I_C(s)) acts as a low-pass filter, (I_R(s)) acts as a band-pass filter and (I_L(s)) acts as a high-pass filter. (d) (I_C(s)) acts as a low-pass filter, (I_L(s)) acts as a band-pass filter and (I_R(s)) acts as a high-pass filter. (e) (I_R(s)) acts as a low-pass filter, (I_C(s)) acts as a band-pass filter and (I_L(s)) acts as a high-pass filter. (f) (I_L(s)) acts as a low-pass filter, (I_R(s)) acts as a band-pass filter and (I_C(s)) acts as a high-pass filter. (g) None of the above. Problem 12. (5 pts) Suppose a pure series RLC circuit, (L = 2*10^{-3} H, C = 5*10^{-2}F, R = 450Omega). Find (V_R(t)) if the input is (V_{in} = 4.5sin(100t)). (a) (V_R(t) = 0.01sin(100t) ) (b) (V_R(t) = 0.01cos(100t) ) (c) (V_R(t) = sin(100t) ) (d) (V_R(t) = cos(100t) ) (e) (V_R(t) = 4.5sin(100t) ) (f) (V_R(t) = 2.75sin(100t)) (g) None of above. Problem 13. (5 pts) Suppose an LTI system has input (x(t) ) and output (y(t)), the two bode plots of the transfer function (H(s) = frac{Y(s)}{X(s)}) is shown below, what is (y(t)) if (x(t) = 100cos(100t+30^o))? In case you can't see the labels clearly, here are the major pair of points: (omega =0.1, |H(s)| = -20,