When E. cоli bаcteriа encоunter а lоw-glucose environment, but lactose is present, the lac operon becomes active. Which of the following describe what initially happens as glucose disappears while lactose is present? Select true or false for each statement. The cAMP-CAP complex binds to the lac operator and directly inhibits transcription of the lac genes. [blank1] LacI releases from the operator when bound by allolactose, allowing RNA polymerase to transcribe the genes needed for increased lactose metabolism. [blank2] Lactose uptake increases. [blank3] LacV digests the genome into small pieces to put the bacteria out of its glucose-free misery. [blank4]