Self-Esteem (X) Self-Hаndicаpping(Y) XDeviаtiоn YDeviatiоn Persоn 1 6 9 0 1 Person 2 3 7 -3 -1 Person 3 4 6 -2 -2 Person 4 7 10 1 2 Person 5 8 6 2 -2 Person 6 5 6 -1 -2 Person 7 9 12 3 4 Mean 6 8 Is there a correlation between participant’s score on self-esteem and self-handicapping? Use α = 0.05, one-tailed, and a critical value of 0.669. a) Calculate the Pearson’s Correlation and show your work. Numerator and work: [CorrNum] Denominator and work: [CorrDem] Correlation coefficient and work: [CorrCoeff] b) Make a decision about the null hypothesis: [CorrDecision] Interpret the results of this experiment: [CorrInterpret] Display the statistical results of your correlation in APA format. Make sure you include effect size, if appropriate. [CorrAPAStats] c) Find the regression equation for predicting someone’s Self-Handicapping score (Y) from their Self-Esteem score. Show your work. SP = 21, SSx = 30, SSy = 34 Mx = 7, My = 9 *Note: these values are NOT the same values as the table you calculated above. beta and work: [beta] y-intercept and work: [y-intercept] d) Does the regression equation you created in part c account for a significant portion of the variance in Self-Handicapping? Use α = 0.05, and critical value of 6.61 to evaluate the F-ratio. SStotal = 34.06, SSresidual = 21.12 n = 7 Mx = 7, My = 9 F-ratio numerator and work: [RegNum] F-ratio denominator and work: [RegDem] Plain English interpretation: [RegInterpret] Display the statistical results of your regression in APA format. You do not need to include effect size. [RegAPAStats]