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Given the relationship covariance chart constructed, report the inbreeding coefficient of Cricket McCue. Report values within the equation as fractions. F[BLANK-1] = 1/2 * COV[BLANK-2] = 1/2 * [BLANK-3] = [BLANK-4]

Of the ancestors identified in Question 10, identify the ancestor(s) that is(are) inbred by clicking on the hot spot(s) (dashed boxes). You can click on more than one option. If none are inbred, click on the blank space to indicate none.

Instructions: Use letters from the pedigree to label equations (e.g., A, MO, M_, etc.). Report values as whole numbers (e.g., 0, 1, 2, etc.) or fractions (1/2, 5/4). The relationship coefficient between Antonio and Teresa can be shown as: R[BLANK-1] = COV[BLANK-2] / (1 + F[BLANK-3])(1 +  F[BLANK-4]) Based on the pedigree and solutions from using the path method, the covariance between Antonio and Teresa is based on: [BLANK-5] ancestor(s) (a number), [BLANK-6] path(s) (a number), and is equal to: [BLANK-7] (a whole number or fraction). Therefore, the relationship coefficient between Antonio and Teresa is equal to: [BLANK-8] (round to 4 decimals).

Which of the following statements about Estradiol is TRUE:

Patient TSH T4 (free Thyroxine) Antimicrosomal antibody A Decreased Decreased Positive B Increased Increased Positive C Normal Decreased Negative D Increased Decreased Positive   What is the thyroid condition of Patient D?

6. A project requires the completion of eight activities. The immediate predecessors (predecessors), normal activity time in weeks (normal time), maximum crashing time in weeks (max crash time), and per week crashing cost (crash cost) are shown in the table below. Activity 1 2 3 4 5 6 7 8 predecessors none none none 1,2 1,2,3 3 5,6 4,7 normal time 6 8 7 9 5 7 4 6 max crash time 3 2 3 4 1 2 2 3 crash cost $650 $550 $700 $465 $500 $385 $720 $810 Using the “normal time” values, find and report the early start times, early finish times, late start times, late finish times, and slack for each activity. Identify the critical path and project completion time.

Consider a locational cost-profit-volume analysis problem where fixed and variable cost information is provided for three location alternatives: A, B, and C, where A has the lowest fixed cost and the highest variable cost and B has the highest fixed cost and the lowest variable cost. Suppose that you compute the breakeven point for alternatives A and C, as well as the breakeven point between alternatives B and C. Carefully explain under what circumstances (and the reason) that it would also be necessary to compute the breakeven point for alternatives A and B.

A company wants to develop a location-distribution plan. They are considering up to five plant locations (Jacksonville, Tallahassee, Ocala, Tampa, Miami) to supply three warehouse distribution center locations (Lake City, Orlando, West Palm). The selected plants will ship units to meet demand at the warehouses. The table below provides relevant cost information, plant capacities, DC capacities, and warehouse demands.     Per unit shipping costs     Warehouse   Jacksonville Tallahassee Ocala Tampa Miami   Demand Lake City $3.90 $3.30 $2.80 $4.90 $7.10   3500 Orlando $4.70 $5.90 $1.90 $4.20 $6.30 3900 West Palm $6.20 $6.80 $5.50 $3.50 $2.70   4100                 Plant capacity 5100 6500 3800 5400 3900   Plant fixed cost $15,000 $12,500 $20,000 $24,000 $19,000     Fixed costs for plants are only realized if they are opened/selected. Prepare an integer linear programming model that, when solved, will determine the plants to be opened and a shipment plan that will meet the demand at the warehouses exactly yet not exceed the capacity limits of the plants. An additional restriction for each selected plant is that it must ship at least 80% of its available capacity. The goal is to minimize the total fixed costs of plants  plus the total variable (per unit) costs of shipment.

Which of the following is a way that bacteria benefit humans?  

Methanotrophs affect global temperature. This is because: