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Simply supported beams loaded with only gravity loads require longitudinal reinforcement along the bottom of the beam.

One of the four primary reasons for using compression reinforcement in beams is increased ductility.

A simply supported beam with dimensions of b = 10 in., h = 24 in., d = 21.5 in., and L = 20 ft supports a uniform service (unfactored) dead load consisting of its own weight plus 1.2 kips/ft and a uniform service (unfactored) live load of 1.0 kips/ft. The concrete is normal-weight concrete. Determine the moment due to the factored loads, Mu.      

Which symbol represents the width of the compression zone in a rectangular reinforced concrete beam?

Determine β1 given that f’c = 8,200 psi.

You are considering a beam design that has dimensions of b = 14 in., h = 24 in., and d = 21.5 in. The beam is singly reinforced with all of the reinforcement in a single row. The concrete strength is 6,700 psi, and the yield strength of the reinforcement is 60,000 psi. What cross-sectional area of reinforcement is needed to achieve a strain in the reinforcement of 0.0075?

The basic strength requirement from ACI 318 is “Reduced nominal strength ​≤ Factored load effects.”

A simply supported beam with dimensions of b = 16 in., h = 22 in., d = 19.5 in., and L = 16 ft supports a uniform service (unfactored) dead load consisting of its own weight plus 1.7 kips/ft and a uniform service (unfactored) live load of 0.9 kips/ft. The concrete is normal-weight concrete. Determine the moment due to the factored loads, Mu.      

Because a slab is thinner than the beams supporting it, the concrete in the slab shrinks more slowly than the concrete in the beams.

In analysis, the objective is to select a suitable cross section, dimensions, concrete strength, etc. given a specific factored design moment. There are many possible solutions.