Written Response/Drawing Questions Instructions T…

Written Response/Drawing Questions Instructions The next six questions are Written Response 1 through 6. These are separate from the Canvas question numbering because you will write or draw your answers by hand. Use the CHEM 210 Exam 3 Answer Sheet if you printed it or copied it onto your own paper before the exam. If not, use blank scrap paper. You may not print the answer sheet during the exam. Clearly number each handwritten answer so it matches the written response question. After you complete Written Response Question 6, continue with the rest of the Canvas exam, beginning with Question 2. Do not upload your handwritten work during the exam. You will submit it after you have fully completed the exam.

On the answer sheet provided to you for the exam, or scrap p…

On the answer sheet provided to you for the exam, or scrap paper, complete all of the parts of the following question: Written Response Question 2 (19 pts): Consider the following SN1 reaction:   Click to Show Image Description A complete chemical reaction scheme showing reactants on the left, conditions, and products on the right. The first reactant is the acetate ion, drawn as a carbonyl group with a double-bonded oxygen at the top, a single-bonded oxygen carrying a negative charge (shown as a circled minus, ⊖) at the lower right, and a single line representing a methyl group at the left. It is labeled “acetate” below the structure. A plus sign separates it from the second reactant, tert-butyl chloride, drawn as a central carbon with three methyl groups branching outward and a chlorine atom (Cl) at the right. Below the reaction arrow, acetic acid is drawn as an HO group connected to a carbonyl, with a methyl group represented by a line, and is labeled “acetic acid.” A single-headed reaction arrow points to the right. The first product is tert-butyl acetate, drawn as a tert-butyl group connected to an oxygen, which is connected to a carbonyl group, followed by a methyl group represented by a line. A plus sign separates it from the second product, the chloride ion (Cl), shown with a circled negative charge (⊖).   Using proper Lewis structures and curved arrow notation, propose a mechanism for this process. Draw an energy diagram. Label: The axes Starting materials Products Transition state(s) EA for rate limiting step DHrxn Draw the structures of the transition state for the rate limiting step and any reactive intermediates. What is the rate equation (rate law) for this reaction?

Please summarize what you have read/learned in week 2. Then…

Please summarize what you have read/learned in week 2. Then meaningfully reflect on what you have learned. For instance, you could relate what you have learned to your life or current events, discuss how your mind has changed due to what you have learned, or offer your thoughts on what you have learned. Those are just suggestions! As long as you are interacting with the content and demonstrating that you are engaging with it in some reflective way, you will receive full credit! Please make sure your answer is at least 400-500 words long. 

On the answer sheet provided to you for the exam, or scrap p…

On the answer sheet provided to you for the exam, or scrap paper, complete all of the parts of the following question: Written Response Question 3 (8 pts): Mechanism – conversion of ROH to RBr with PBr3 with stereochemical inversion. In the space below show how this conversion occurs using 2-butanol as the starting material with curved arrows for the movement of electrons, proper Lewis structures and formal charges.  Be sure to show how the stereochemistry is inverted.   Click to Show Image Description A chemical reaction scheme showing a starting material on the left, a reagent above the arrow, and a product on the right. The starting material is 2-butanol, drawn as a four-carbon zigzag line structure. At the second carbon of the chain, a hydroxyl group (OH) is attached via a bold wedge bond, indicating it projects toward the viewer and conveying a specific configuration at that stereocenter. The reagent phosphorus tribromide is written as PBr₃ above a single-headed reaction arrow pointing to the right. The product on the right is also drawn as a four-carbon zigzag line structure. At the second carbon of the chain, a hydroxyl group (OH) is attached via a dashed bond, indicating it projects away from the viewer, conveying the opposite configuration at that stereocenter relative to the starting material.