4.6 g of Al and 3.6 g of O2{“version”:”1.1″,”math”:”O2″} wer…

4.6 g of Al and 3.6 g of O2{“version”:”1.1″,”math”:”O2″} were allowed to react according to the following chemical equation: 4 Al + 3 O2 →2 Al2O3{“version”:”1.1″,”math”:”4 Al + 3 O2 →2 Al2O3″} Calculate theoretical yield, in grams, of aluminum oxide. Type only correctly rounded number with no unit, for example 5.9 Molar masses: Al 26.98  O 16.00 _______