Gabrielle is three months behind on her mortgage, and her le…

Gabrielle is three months behind on her mortgage, and her lender filed negative information affecting her credit rating. Gabrielle mailed one monthly payment to the lender along with a letter stating that she was making the payment on the condition that the lender remove negative material sent to credit reporting agencies affecting her credit rating. The lender cashed the check but did not remove the negative information. Gabrielle sues the bank for breach of contract. Which of the following is the most likely result?

Use the example below to solve the exercise that follows….

Use the example below to solve the exercise that follows. Example: Write the equation of the circle in standard form. Then identify the center and radius.               x2-6x+y2+4y-9=3{“version”:”1.1″,”math”:”x2-6x+y2+4y-9=3″}Solution:             x2-6x+y2+4y-9=3×2-6x+y2+4y=12×2-6x+9+y2+4y+4=12+9+4(x-3)2+(y+2)2=25{“version”:”1.1″,”math”:”x2-6x+y2+4y-9=3×2-6x+y2+4y=12×2-6x+9+y2+4y+4=12+9+4(x-3)2+(y+2)2=25″}Answer:  Center is (3, -2){“version”:”1.1″,”math”:”(3, -2)”} and  r=5{“version”:”1.1″,”math”:”r=5″} Exercise: Write the equation of the circle in standard form. Then identify the center and radius.              x2+2x+y2-14y+43=0{“version”:”1.1″,”math”:”x2+2x+y2-14y+43=0″}Show your work in the box below.

Use the example below to solve the exercises that follow.   …

Use the example below to solve the exercises that follow.         Example:Determine whether the given polynomial is a perfect square trinomial, then factor it.          x2+14x+49{“version”:”1.1″,”math”:”x2+14x+49″} Solution:Determine whether the given polynomial is a perfect square trinomial (Step 1&2), then factor it (Step 3).Step 1: Check if the first and third terms are both perfect squares with positive coefficients:           x2 = (x)2{“version”:”1.1″,”math”:”x2 = (x)2″}  and 49 = (7)2{“version”:”1.1″,”math”:”49 = (7)2″}Step 2: Identify a{“version”:”1.1″,”math”:”a”}  and b{“version”:”1.1″,”math”:”b”} , and determine if the middle term equals 2ab{“version”:”1.1″,”math”:”2ab”}  or -2ab{“version”:”1.1″,”math”:”-2ab”}           a = x{“version”:”1.1″,”math”:”a = x”}  and b = 7{“version”:”1.1″,”math”:”b = 7″}          2ab = 2(x)(7) =14x{“version”:”1.1″,”math”:”2ab = 2(x)(7) =14x”}Step 3:Use the first formula if the middle term is positive, or the second, if the middle term is negative:        x2+14x+49=(x+7)2 {“version”:”1.1″,”math”:”x2+14x+49=(x+7)2 ”}Exercise 1:Determine whether the given polynomial is a perfect square trinomial by demonstrating in the box below the steps 1 and 2 from the example . If yes, then factor it. If not, then state so.        w2-16w+64{“version”:”1.1″,”math”:”w2-16w+64″}     Exercise 2:Determine whether the given polynomial is a perfect square trinomial by demonstrating in the box below the steps 1 and 2 from the example. If yes, then factor it. If not, then state so.          z2 +10z+100{“version”:”1.1″,”math”:”z2 +10z+100″}     Show all steps using the Graphical Equation Editor.