According to the following reaction, what mass of PbCl2 can…

According to the following reaction, what mass of PbCl2 can form from 325 mL of 0.110 M KCl solution?  Assume that there is excess Pb(NO3)2. KCl = 74.548 g/mol; Pb(NO3)2  = 331.208 g/mol; PbCl2 = 278.1 g/mol; KNO3 = 101.102 g/mol             2 KCl(aq) + Pb(NO3)2(aq)  →  PbCl2(s) + 2 KNO3(aq)