Strict performance and substantial performance mean the same thing.
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Debra offers to tutor Karen for $20 per hour. Karen respond…
Debra offers to tutor Karen for $20 per hour. Karen responds, “I won’t pay $20, but I will pay $10 for your tutoring services.” Which of the following is accurate?
All contracts have to be in writing in order to be enforceab…
All contracts have to be in writing in order to be enforceable.
Twenty years after you take this class you are successful an…
Twenty years after you take this class you are successful and wealthy. Knowing that Business Law was the key to your success, you look up your old professor and send a letter saying, “Because you helped me so much, I am going to send you a check for $100,000.” Later you come to your senses and do not send the check. Your old professor sues you for the money. What result?
What is the difference between common law contracts and UCC…
What is the difference between common law contracts and UCC contracts?
A means of identifying each account as an asset, liability,…
A means of identifying each account as an asset, liability, or owner’s equity.
A special type of owner’s equity account set up to record th…
A special type of owner’s equity account set up to record the owner’;s withdrawal of cash from the business.
Engine coolant for cars is made of a solution of ethylene gl…
Engine coolant for cars is made of a solution of ethylene glycol. If 27.7 g of ethylene glycol release 688 J of heat to finish at a temperature of 32.5 °C, what was the initial temperature? The specific heat capacity of ethylene glycol is 2.42 J/g°C. Must show your work (scratch paper) to receive credit.
Calculate the ∆H°f for benzene (C6H6) from the following dat…
Calculate the ∆H°f for benzene (C6H6) from the following data: ∆H°fCO2 = – 393.5 kJ/mol∆H°fH2O = – 285.8 kJ/mol 2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(l) ∆ Hrxn= -6534 kJMust show your work (scratch paper) to receive credit.
Calculate the ∆H°f for benzene (C6H6) from the following dat…
Calculate the ∆H°f for benzene (C6H6) from the following data: ∆H°fCO2 = – 393.5 kJ/mol∆H°fH2O = – 285.8 kJ/mol 2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(l) ∆ Hrxn= -6534 kJMust show your work (scratch paper) to receive credit.