Which of the following cannot be used as a precursor for gluconeogenesis in the human liver?
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The reactions of glycolysis and gluconeogenesis are regulate…
The reactions of glycolysis and gluconeogenesis are regulated through the conversion of fructose-6-phosphate and fructose-1,6-bisphosphate, and vice versa. The following statements about this regulation are correct EXCEPT
Adding 2,4-dinitrophenol to an actively respiring cell tissu…
Adding 2,4-dinitrophenol to an actively respiring cell tissue culture would likely result in all of the following, EXCEPT
What phosphoryl donor is used in the reaction of converting…
What phosphoryl donor is used in the reaction of converting oxaloacetate to phosphoenolpyruvate?
What enzyme catalyzes the anaplerotic reaction of oxaloaceta…
What enzyme catalyzes the anaplerotic reaction of oxaloacetate formation from pyruvate?
The liver isozyme of pyruvate kinase can be inhibited by cov…
The liver isozyme of pyruvate kinase can be inhibited by covalent modification when PKA is stimulated by increased cAMP concentration. However, the muscle isozyme is not affected by covalent modification. As a result,
What enzyme catalyzes the anaplerotic reaction of oxaloaceta…
What enzyme catalyzes the anaplerotic reaction of oxaloacetate formation from pyruvate?
Cytochromes are:
Cytochromes are:
Which complex mediates the transfer of electrons from a memb…
Which complex mediates the transfer of electrons from a membrane-soluble carrier to a water-soluble carrier in the ETC?
Consider the following C implementation of a hash table:…
Consider the following C implementation of a hash table: #include#define HASH_SIZE 10struct bucket { char* string; struct bucket* next;};typedef struct bucket Bucket;Bucket table[HASH_SIZE];//hash table… unsigned hash(char* key) { unsigned val = 0; while (*key) val = *(key++) + 2 * val; return val % HASH_SIZE;}void init() {//initialize the buckets of my hash table… int i; for (i = 0; i < HASH_SIZE;i++) table[i].string = NULL;}void printHashTable() { int i = 0; Bucket* iterator; for (; i < HASH_SIZE; i++) if (table[i].string) {//not an empty bucket iterator = &table[i];//head of linked list while (iterator) { printf("%s\n", iterator->string); iterator = iterator->next;//advances the iterator… } }}int insert(char* word) { if (search(word)) return 0;//duplicate value, do not add it to the hash table! unsigned index = hash(word); if (table[index].string == NULL) {//empty bucket table[index].string = (char*)malloc(strlen(word) + 1); strcpy(table[index].string, word); table[index].next = NULL; return 1;//successful insert } char* currentHeadOfLinkedList = table[index].next; table[index].next = (Bucket*)malloc(sizeof(Bucket)); table[index].next->string = (char*)malloc(strlen(word) + 1); strcpy(table[index].next->string, word); table[index].next->next = currentHeadOfLinkedList; return 1;}int search(char* word) {//returns 1 if successful and 0 if not int i = hash(word); Bucket* iterator;//link list iterator… if (table[i].string) {//not an empty bucket iterator = table + i;//head of linked list while (iterator) { if (!strcmp(iterator->string, word))//matched return 1; iterator = iterator->next; } } return 0;//unsuccessful search} Also, assume that the following main function uses the hash table to store some strings: main() { int i; init(); char* strings[] = { “AB”, “CD”, “EF”, “GH”, “CD” }; for (i = 0; i < 5;i++) insert(strings[i]); printHashTable();} Answer the following questions: (10 points) Find the hash value of every member of the strings array. The hash value is calculated and returned by the hash function (Hint: ASCII values of letters A, B, C, ... are 65, 66, 67, etc.) (10 points) What's the output of the given C program.