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A tensile test was performed on a specimen with a circular cross section. The diameter was measured to be 1.000 inch. Two marks were made along the length of the specimen and were measured to be 2.850 inches apart. This distance is defined as the gage length, and all length measurements were made between the two marks. The specimen was loaded to failure. Fracture occurred at a load of 29,000 pounds. The specimen was then reassembled, and the diameter and gage length were measured to be 0.583 inch and 3.141 inches. Determine the elongation as a percentage.

The fundamental requirement of structural design is that required strength is _______ available strength.

For LRFD, the resistance factor for yielding is larger than the resistance factor for fracture.

Working loads are also known as _______.

To prevent excessive deformation, the load on the gross section must be small enough that the stress on the gross section is less than the yield strength.

A 0.80 in. x 3.2 in. plate is connected to a gusset with three 1-1/4 in. bolts. Standard sizing is used for the bolt holes. What is the net area of the plate?

All building codes in the United States are the same and come from a national standard created by Congress.

For LRFD, the resistance factor for fracture is ____.

A tensile test was performed on a specimen having a circular cross section with a diameter of 0.500 inch. The gage length (the length over which the elongation is measured) is 1.5 inches. For a load of 15.0 kips, the elongation was 0.00805 inches. If the load is assumed to be within the linear elastic range of the material, determine the modulus of elasticity.

A 1/2 in. x 5.0 in. plate is connected to a gusset with four 7/8 in. bolts. Standard sizing is used for the bolt holes. The steel is ASTM A572 Grade 60: Fy = 60 ksi, Fu = 75 ksi. Assume that Ae = An. Compute the design strength for LRFD.