The reaction of 55.0 g methylamine (CH3NH2) with excess acet…

The reaction of 55.0 g methylamine (CH3NH2) with excess acetic acid (C2H4O2) produces metylacetamide (CH3NH2) and water: CH3NH2 + C2H4O2 –> C3H7NO + H2O. The reaction has an experimental yield of 76 g methylacetamide. What is the percent yield of metylacetamide? Answer in % to the ones place.  Use these molecular masses: Molecular Masses Compound Molecular Mass (g/mol) methylamine 31.0 acetic acid 60.0 methylacetamide 73.0 water 18.0