By using the information given below, calculate the concentration of NaOH.The volume of NaOH used in the titration = 25.00 mLVolume of 0.23 M HCl used to neutralize the 25.0 mL NaOH = 17.7 mL. (Concentration = moles/volume(L) ; Moles = concentration x volumeNaOH(aq) + HCl(aq) –> NaCl(aq) + H2O(l)
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