Deathcare that minimizes the use of energy in service, and offers products that ban the use of toxic or hazardous materials is called
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The burning chamber in a crematory is called a
The burning chamber in a crematory is called a
What is the proper term used to describe the initial notific…
What is the proper term used to describe the initial notification informing a funeral home that a death has occurred?
Consider the following half-cell reactions: Zn2+(aq) + 2e-…
Consider the following half-cell reactions: Zn2+(aq) + 2e- ↔ Zn(s) Ecell = -0.76 V Cu2+(aq) + 2e- ↔ Cu(s) Ecell = +0.34 V Identify the species (element or ion) that is acting as the reducing agent Hint: The half-cell with the highest positive potential gets reduced
Two half-cell reactions are shown below: Fe2+(aq) + 2e- …
Two half-cell reactions are shown below: Fe2+(aq) + 2e- ↔ Fe(s) Ecell = – 0.44 V Cu2+(aq) + 2e- ↔ Cu(s) Ecell = +0.34 V Hint: The half-cell with the highest positive potential gets reduced. the other half-cell must get oxidized. Find the Gibbs free energy for the above cell reaction (ΔG = -nFE: F = 96485 C, n = no. of electrons and E = cell potential). Use the cell voltage you received in questions 21.
An emission of gamma radiation from a radioactive element
An emission of gamma radiation from a radioactive element
Consider the following half-cell reactions: Zn2+(aq) + 2e-…
Consider the following half-cell reactions: Zn2+(aq) + 2e- ↔ Zn(s) Ecell = -0.76 V Cu2+(aq) + 2e- ↔ Cu(s) Ecell = +0.34 V If a cell is built by combining above two half-cells, what will be its cell potential? Hint: The half-cell with the highest positive potential gets reduced: Ecell= E(cathode) – E(anode)
If Al3+(aq) = 0.36 M, Sn4+ (aq) = 0.086 M and Sn2+(aq) = 0.5…
If Al3+(aq) = 0.36 M, Sn4+ (aq) = 0.086 M and Sn2+(aq) = 0.54 M, calculate the Ecell of this non standard cell Use: Al3+(aq) + 3e- ↔ Al(s) Ecell = -1.676 V Sn4+(aq) + 2e- ↔ Sn2+(aq) Ecell = 0.154 v
Based on the Gibbs free energy you received for question (25…
Based on the Gibbs free energy you received for question (25), calculate the equilibrium constant for the reaction. Use ΔG = -RT ln K: Temperature 25 Celsius, R = 8.314 J / mol. K
HCl, HBr and HI are strong acids; however, HF is a weak acid…
HCl, HBr and HI are strong acids; however, HF is a weak acid. What is the best explanation for this phenomenon?