Consider the following half-cell reactions: Zn2+(aq)  +  2e-…

Consider the following half-cell reactions: Zn2+(aq)  +  2e-  ↔  Zn(s)  Ecell = -0.76 V Cu2+(aq)  +  2e-  ↔  Cu(s)  Ecell = +0.34 V Identify the species (element or ion) that is acting as the reducing agent Hint: The half-cell with the highest positive potential gets reduced

Two half-cell reactions are shown below: Fe2+(aq)  +  2e-   …

Two half-cell reactions are shown below: Fe2+(aq)  +  2e-   ↔  Fe(s)     Ecell = – 0.44 V Cu2+(aq)  +  2e-  ↔  Cu(s)    Ecell = +0.34 V Hint: The half-cell with the highest positive potential gets reduced. the other half-cell must get oxidized. Find the Gibbs free energy for the above cell reaction (ΔG = -nFE: F = 96485 C, n = no. of electrons and E = cell potential). Use the cell voltage you received in questions 21.

Consider the following half-cell reactions: Zn2+(aq)  +  2e-…

Consider the following half-cell reactions: Zn2+(aq)  +  2e-  ↔  Zn(s)  Ecell = -0.76 V Cu2+(aq)  +  2e-  ↔  Cu(s)  Ecell = +0.34 V If a cell is built by combining above two half-cells, what will be its cell potential?  Hint: The half-cell with the highest positive potential gets reduced: Ecell= E(cathode) – E(anode)