Going from room temperature, 298 K, to {T} K, the rate of a…

Going from room temperature, 298 K, to {T} K, the rate of a reaction doubles. Calculate the activation energy for the reaction in kJ/mol.  R = 8.314 x 10-3 kJ/mol Answer format:  Enter in standard notation, not scientific using 3 sig figs.  Do not include units.