Determine the maximum actual shear stress in the following beam. Do not reduce the shear based on NDS Section 3.4.3. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 240 lbPLr = 1,440 lbLoad combination:D + LrSpan:L = 13 ftMember size:4 x 10Stress grade and species:Select Structural Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC > 19 percentLive load deflection limit:Allow. Δ ≤ L/360
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For glulams, the bearing area factor would be used to determ…
For glulams, the bearing area factor would be used to determine which of the following adjusted design values? Select all that apply.
Determine the ASD adjusted design bending strength, Fb’, for…
Determine the ASD adjusted design bending strength, Fb’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 560 lbPLr = 2,240 lbLoad combination:D + LrSpan:L = 11 ftMember size:4 x 12Stress grade and species:No. 1 Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC > 19 percentLive load deflection limit:Allow. Δ ≤ L/360
Determine the volume factor, Cv, for a 3.125” x 21” Douglas…
Determine the volume factor, Cv, for a 3.125” x 21” Douglas Fir glulam that is 26 feet long and simply supported.
For glulams, the curvature factor would be used to determine…
For glulams, the curvature factor would be used to determine which of the following adjusted design values? Select all that apply.
Determine the ASD adjusted design shear strength, Fv’, for t…
Determine the ASD adjusted design shear strength, Fv’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:wD = 260 lb/ftwLr = 180 lb/ftLoad combination:D + LrSpan:L = 7 ftMember size:4 x 10Stress grade and species:No. 1 Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC < 19 percentLive load deflection limit:Allow. Δ ≤ L/360
Determine the ASD adjusted design compression strength paral…
Determine the ASD adjusted design compression strength parallel to grain, Fc’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 480 lbPLr = 1,120 lbLoad combination:D + LrSpan:L = 9 ftMember size:4 x 14Stress grade and species:Select Structural Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC < 19 percentLive load deflection limit:Allow. Δ ≤ L/360
Determine the ASD adjusted design bending strength, Fb’, for…
Determine the ASD adjusted design bending strength, Fb’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 280 lbPLr = 800 lbLoad combination:D + LrSpan:L = 9 ftMember size:4 x 10Stress grade and species:No. 1 & Better Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC > 19 percentLive load deflection limit:Allow. Δ ≤ L/360
Determine the maximum actual shear stress in the following b…
Determine the maximum actual shear stress in the following beam. Do not reduce the shear based on NDS Section 3.4.3. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:wD = 200 lb/ftwLr = 270 lb/ftLoad combination:D + LrSpan:L = 10 ftMember size:4 x 12Stress grade and species:No. 1 Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC < 19 percentLive load deflection limit:Allow. Δ ≤ L/360
Determine the maximum bending moment in the following beam….
Determine the maximum bending moment in the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 560 lbPLr = 1,440 lbLoad combination:D + LrSpan:L = 11 ftMember size:4 x 6Stress grade and species:No. 1 & Better Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC > 19 percentLive load deflection limit:Allow. Δ ≤ L/360