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@X@user.full_name@X@ @GMU: When 0.1901 g of aspirin was dissolved in 100.5 mL of water, the osmotic pressure at 10.92°C was 0.2498 atm. What is the formula mass of this compound?

@X@user.full_name@X@ @GMU: What is the solubility in g/L of O2 at a partial pressure of 653.9 torr, if the solubility at a partial pressure of 487.7 torr is 0.02833 g/L?

John Schreifels @GMU: When 7.237 g of lysine was dissolved in 109.9 g of benzene, the freezing point was 276.3 K. What is the formula mass of this compound? The freezing point depression constant for benzene is 5.12 (°C*kg)/mol. The melting point and boiling points are 5.50°C and 80.10°C, respectively.

@X@user.full_name@X@ @GMU: A mixture containing an initial concentration of 0.1506 M for H2 and 0.1223 M for Br2 is allowed to come to equilibrium (see reaction below). What must be the equilibrium concentration of HBr?H2(g) + Br2(g) → 2HBr(g) Kc = 1.42e3

Which of the following conditions will cause equilibrium to shift to the left?2NH3(g) + ⇋ N2(g) + 3H2(g)

@X@user.full_name@X@ @GMU: Determine the rate of consumption of I− if the rate for formation of I2 is 0.333 M/s. Use the reaction below.IO3− + 5I− + 6H+ → 3I2 + 3H2O

@X@user.full_name@X@ @GMU: The following data was obtained by the method of initial rates. What is the rate law for the reaction of A with B to produce product? [A]o [B]o Rate, M/s 0.289 0.300 2.10e-7 0.483 0.300 4.54e-7 0.289 0.552 3.87e-7

@X@user.full_name@X@ @GMU: Determine the rate of formation of I3− if the rate for formation of SO42− is 0.400 M/s. Use the reaction below.3I−(aq)+ S2O82−(aq) → I3−(aq) + 2SO42−(aq)

@X@user.full_name@X@ @GMU: Initially there were equilibrium concentrations of 0.3075 M A, 0.2127 M B, and 0.1435 M C. Which change will cause the equilibrium to shift from right to left if the reaction is exothermic? Use the reaction below.2A(aq) → 3 B(aq) +3 C(aq) K = 0.406

@X@user.full_name@X@ @GMU: What is the activation energy (in kJ/mol) for the reaction below if the rate constants are 1.050e-3 M-1/2s-1 at 486.00°C and 2.82e-3 M-1/2s-1 at 509.55°C?CH3CHO(g) → CH4(g) + CO(g)