The equilibrium constant, Kc = 9.10 x 10-2, for the reaction…

The equilibrium constant, Kc = 9.10 x 10-2, for the reaction below at 298 K.                                                                                       X + Y à 2Z  What is the value of ∆G in kJ when [X] = {x} M, [Y] = .0100 M, [Z] = .0100 M  R = 8.314 J/K·mol.  ∆G = R T ln(Q/K)    Hint:  pay attention to units Answer format:  Enter in standard (not scientific) notation with 3 sig figs in kJ.  Do not enter the units.