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Determine the ASD adjusted design bending strength, Fb’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 240 lbPLr = 960 lbLoad combination:D + LrSpan:L = 11 ftMember size:4 x 6Stress grade and species:No. 1 Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC > 19 percentLive load deflection limit:Allow. Δ ≤ L/360

A wood member is loaded as shown. Using ASD, determine the maximum axial stress in the member. Assume normal temperatures, no incising, and that all loads act in the directions shown. Ignore the weight of the member.Load:PD = 4,000 lbPL = 0 lbPLr = 0 lbPS = 0 lbPR = 0 lbPW = 8,500 lbPE = 8,500 lbQD = 0 lbQL = 1,500 lbQLr = 0 lbQS = 2,000 lbQR = 3,000 lbQW = 0 lbQE = 0 lbSpan:L = 13 ft Member size:4 x 14 Stress grade and species:Select Structural Douglas Fir-Larch Unbraced length:lu = L/2 = 6.5 ft Moisture content:MC < 19 percent 

Determine the ASD adjusted design bending strength, Fb’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:wD = 240 lb/ftwLr = 390 lb/ftLoad combination:D + LrSpan:L = 12 ftMember size:4 x 12Stress grade and species:No. 1 & Better Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC < 19 percentLive load deflection limit:Allow. Δ ≤ L/360

For deflection calculations, the adjusted modulus of elasticity Ex’ for a hardwood glulam beam 16F-V3 with ASD load combination (D + 0.6W), under 16% moisture content, and a constant temperature of 140°F is _______.

Determine the maximum actual shear stress in the following beam. Do not reduce the shear based on NDS Section 3.4.3. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 600 lbPLr = 960 lbLoad combination:D + LrSpan:L = 7 ftMember size:4 x 8Stress grade and species:No. 2 Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC < 19 percentLive load deflection limit:Allow. Δ ≤ L/360

Determine the ASD adjusted design shear strength, Fv’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:wD = 100 lb/ftwLr = 450 lb/ftLoad combination:D + LrSpan:L = 11 ftMember size:4 x 8Stress grade and species:Select Structural Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC < 19 percentLive load deflection limit:Allow. Δ ≤ L/360

Determine the ASD adjusted design bending strength, Fb’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 320 lbPLr = 800 lbLoad combination:D + LrSpan:L = 11 ftMember size:4 x 14Stress grade and species:No. 1 & Better Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC < 19 percentLive load deflection limit:Allow. Δ ≤ L/360

Determine the maximum actual bending stress in the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 240 lbPLr = 1,440 lbLoad combination:D + LrSpan:L = 6 ftMember size:4 x 12Stress grade and species:No. 2 Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC > 19 percentLive load deflection limit:Allow. Δ ≤ L/360

Determine the ASD adjusted design tension strength, Ft’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 600 lbPLr = 960 lbLoad combination:D + LrSpan:L = 14 ftMember size:4 x 8Stress grade and species:No. 1 Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC < 19 percentLive load deflection limit:Allow. Δ ≤ L/360

Determine the maximum actual shear stress in the following beam. Do not reduce the shear based on NDS Section 3.4.3. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 360 lbPLr = 1,600 lbLoad combination:D + LrSpan:L = 13 ftMember size:4 x 8Stress grade and species:No. 2 Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC > 19 percentLive load deflection limit:Allow. Δ ≤ L/360