If the percent yield for the reaction is known to be 62.3%,…

If the percent yield for the reaction is known to be 62.3%, what should your actual yield of ClF3(g) (molar mass = 92.45 g/mol) be if you react 0.380 mol of Cl2(g) (molar mass = 70.90 g/mol) with 3.77 mol of F2(g) (molar mass = 38.00 g/mol)? Cl2(g) + 3F2(g) → 2ClF3(s)