Determine the reaction force at B. Let w = 15 lb/in., a = 53 in., and EI = 56 × 106 lb·in.2.
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Determine the beam slope at B. Let w = 1.0 kip/ft, L1 = 38 f…
Determine the beam slope at B. Let w = 1.0 kip/ft, L1 = 38 ft, and L2 = 25 ft. Assume EI = constant.
The beam supports a single live load of 2,500 lb. Determine…
The beam supports a single live load of 2,500 lb. Determine the maximum positive moment that can be developed at point B. Assume the support at A is a pin and C is a roller. The influence lines for VB and MB are shown, along with the peak values of the influence lines.
Using the method of consistent deformations, determine the m…
Using the method of consistent deformations, determine the magnitude of the reaction at D. Let w = 16 kN/m and L = 7 m.
Determine the fixed end moment FEMAB. Let P = 20 kips, L1 =…
Determine the fixed end moment FEMAB. Let P = 20 kips, L1 = 30 ft, and L2 = 15 ft. Assume EI = constant.
Using the method of consistent deformations, determine the f…
Using the method of consistent deformations, determine the force in member AD. Let P = 17 kN, L1 = 6 m, and L2 = 3 m. Assume EA = constant.
Identify the moment equation that corresponds to MAB. Let w…
Identify the moment equation that corresponds to MAB. Let w = 2.0 kip/ft, L1 = 16 ft, and L2 = 20 ft. Assume EI = constant.
Using the slope-deflection equations below, determine the be…
Using the slope-deflection equations below, determine the beam slope at C. Let P1 = 12 kips, P2 = 11 kips, L1 = 20 ft, L2 = 10 ft, and L3 = 15 ft. Assume EI = constant.MAC = EIθC / 15 + 26.67MCA = EIθC / 7.5 + –53.33MCE = EIθC / 7.5 + 41.25MEC = EIθC / 15 + –41.25
On this quiz, “maximum” refers to the highest vertical point…
On this quiz, “maximum” refers to the highest vertical point on the influence graph and “minimum” refers to the lowest vertical point on the graph.Draw the influence line for the vertical reaction at A. What is the line’s minimum value? Let L1 = 4 m and L2 = 13 m.
Determine the deflection at B that would be caused by the co…
Determine the deflection at B that would be caused by the concentrated moment if the middle support was not there. Let M = 18,800 lb·in., a = 80.83 in., b = 59.17 in., and EI = 57 × 106 lb·in.2. Note that b = (a + b)[1 – sqrt(3)/3].