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what will the marginal cost equal for production at quantity (Q) level 4? Q P TC TR MR MC Profit 0 $5 $9         1 $5 $10         2 $5 $12         3 $5 $15         4 $5 $19         5 $5 $20         6 $5 $30         7 $5 $45        

Manuel like to spend his part of his monthly income on buying fitness membership and perfumes. Each fitness membership cost $25 per month, with marginal utility is 50.If his Marginal utility from buying perfumes is 160, how much it costs Manuel to buy each perfume?

If P < AVCAVC = average variable cost

Graph 1 In the graph above, which point is considered a high level of utility point?“high” level of utility.

If P > AVC but P < ATC, then the firm is:AVC = average variable costATC = average total cost

Consider the following multi-threaded pseudocode. Thread A: 1. lock (& mutex ); 2. if( queue . empty ()) { 3. cond_wait (&cv , & mutex ); 4. } 5. data = queue .pop (); 6. unlock (& mutex ); Thread B: 1. lock (& mutex ); 2. queue . insert ( data ); 3. cond_signal (& cv ); 4. unlock (& mutex ); Identify all bugs, if any exist. If you can define the bugfix then you will get extra credit A. Thread A Line 2 B. Thread A Line 3 C. Thread B Line 2 D. Thread B Line 3 E. No bugs    

Why does Shortest Job First (SJF) scheduling give us optimal time, but its implementation is not feasible in real life?

threads in a program share Code section, Data section, and all the open files. However, each thread will have its own [Ans1] and [Ans2].

Consider the following multi-threaded C code. 1: void send_money ( acct * src , acct * dst , int amount ) { 2: lock (& src -> mutex ); 3: if (src -> value >= amount ) { 4: src -> value -= amount ; 5: lock (& dst -> mutex ); 6: dst -> value += amount ; 7: unlock (& dst -> mutex ); 8: } 9: unlock (& src -> mutex ); 10: } (a) Describe any bug(s) you see along with the line number. You need to justify your answer (b) Now revise the code to fix the bug. (you need to write the entire code (whatever lines given) with the change)

In the Producer code, the counter++ is implemented as     register1 = counter     register1 = register1 + 1     counter = register1 In the consumer code, the counter– is implemented as     register2 = counter     register2 = register2 – 1     counter = register2 Assume the producer produces one item and does counter++, and the consumer consumes it and runs counter– Consider this execution interleaving with “counter = 3” initially: S0: producer execute register1 = counter        S1: producer execute register1 = register1 + 1   S2: consumer execute register2 = counter     S3: consumer execute register2 = register2 – 1  S4: producer execute counter = register1         S5: consumer execute counter = register2     Hence, the final value of the counter for the producer will be [Ans1], and the consumer will be [Ans2] where the correct value of the counter will be [Ans3]