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In lexicalized signs, every letter of the original fingerspelled word is always fully formed.

According to the 4.1 “Taking off” Snapshot, why is it important to sign the message equivalent to the intended meaning?

What does the prefix “lexical” signify?

(06.04 MC) One link in a chain was made from a cylinder that has a radius of 2 cm and a height of 20 cm. How much plastic coating would be needed to coat the surface of the chain link? Use 3.14 for π.

(06.03 MC) What is the weight (in grams) of a liquid that exactly fills a 465 milliliter container if the density of the liquid is 0.982? Round to the nearest hundredth when necessary and only enter numerical values, which can include a decimal point.

(06.03 LC) Ronald is calculating the density of oranges in a crate. He knows the number of oranges in the crate and the volume of the crate. Which of the following formulas can be used to calculate the density of oranges in the crate?

(06.04 MC) One link in a chain was made from a cylinder that has a radius of 2.5 cm and a height of 22 cm. How much plastic coating would be needed to coat the surface of the chain link? Use 3.14 for π.

(06.01 MC) Jude says that the volume of a square pyramid with base edges of 12 in and a height of 10 in is equal to the volume of a cylinder with a radius of 6.77 in and a height of 10 in. Jude rounded his answers to the nearest whole numbers. Examine Jude’s calculations. Is he correct? Volume of Square Pyramid Volume of Cylinder V = B(h) V = πr2h V = (144)(10) V = π(6.772)(10) V = (1440) π(45.8329)(10) V = 480 in3 V = π(458.329)   V ≈ 480 in3

(06.03 MC) A large emerald with a mass of 812.04 grams was recently discovered in a mine. If the density of the emerald is 2.76, what is the volume? Round to the nearest hundredth when necessary, and only enter numerical values, which can include a decimal point.

(06.01 MC) Jude says that the volume of a square pyramid with base edges of 7 in and a height of 7 in is equal to the volume of a cylinder with a radius of 7 in and a height of 7 in. Jude rounded all answers to the nearest whole number. Examine Jude’s calculations. Is he correct? Volume of Square Pyramid Volume of Cylinder V = B(h) V = r2h V = 49(7) V = (72)(7) V = 343 in3 V = 343 in3