An unknown metal ball weighing 46.60 g was heated to 73 Cels…

An unknown metal ball weighing 46.60 g was heated to 73 Celsius and placed inside a calorimeter with 60.0 g of water at 21 Celsius. After allowing the system to equilibrate, the final temperature of the water reached 31 Celsius. Calculate the specific heat of the unknown metal. Heat = mass x specific heat capacity x temperature changeSpecific heat of water = 4.184 J / (g . °C)Hint: use the following equationheat absorbs by the metal = -(heat given out by the hot water)