A movie theater has seats arranged in a rectangular grid of rows and columns. The grid stores the value true to mean that the seat is available for purchase and false to represent the seat is not available. Below is a small sized grid to demonstrate this: false true true true false false true false true false false false false false true true false true false true true true true false You will complete the method below that finds a block of adjacent seats in a row, if it exists. If it does not exist, -1 will be returned. If a block of seats is available, the index of the lowest column number will be returned. The following table shows different possible calls to the method and the resulting int returned: call result explanation find(available, 0, 2) 1 a block of 2 seats exists in row 0 starting a col 2 find(available, 0, 4) -1 no block of 4 seats in row 0 exists find(available, 1, 2) 6 a block of 2 seats exists in row 1 starting a col 6 find(available, 2, 2) 3 a block of 2 seats exists in row 2 starting a col 3 find(available, 2, 4) 3 a block of 2 seats exists in row 2 starting a col 4 Complete the dropdowns to write the method. Ignore any small syntax errors, they are unintentional. public static int find(boolean [][] available, int row, int seatsNeeded) { int countAdjacent = 0; int firstSeatAvailable = 0; for [line1] if (available[row][col] == true) { if [line2] [line3] } [line4] if [line5] [line6] } else { [line7] } } else { [line8] } } [line9] }
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