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For an electron incident on the potential barrier below, with E

Identify this area of the uterus:

For the following problem, use a separate sheet of paper to solve the problem and then upload your solution at the following link: https://canvas.dccc.edu/courses/28465/assignments/575258   Your work must be shown for full credit.  The answer alone is only worth 1 point.    A solution is prepared by dissolving 7.00 g of glycerin (C3H8O3) in 201 g of ethanol (C2H5OH). The freezing point of pure ethanol is -114.6°C at 1 atm. The molal-freezing-point-depression constant (Kf) for ethanol is 1.99°C/m. The molar masses of glycerin and of ethanol are 92.1 g/mol and 46.1 g/mol, respectively. Calculate the freezing point of the solution.   

The height above the ground of a stone thrown upwards is given by s(t), where t is measured in seconds. After 1 second the height of the stone is 48 feet above the ground, and after 1.5 seconds the height of the stone is 60 feet above the ground. Find the average velocity of the stone over the time interval [1,1.5]

Assume the function g satisfies the inequality 1≤g(x)≤sin(2x)+1{“version”:”1.1″,”math”:”1≤g(x)≤sin(2x)+1″} for all values of x near 0. Find limx→0 g(x){“version”:”1.1″,”math”:”limx→0 g(x)”}

Evaluate the limx→∞ f(x){“version”:”1.1″,”math”:”limx→∞ f(x)”} and the limx→-∞f(x){“version”:”1.1″,”math”:”limx→-∞f(x)”} for f(x)=4×3+11-x3{“version”:”1.1″,”math”:”f(x)=4×3+11-x3″}

Find the limit limx→2-x-2{“version”:”1.1″,”math”:”limx→2-x-2″}

For the following problem, use a separate sheet of paper to solve the problem and then upload your solution at the following link: https://canvas.dccc.edu/courses/28465/assignments/575258   Your work must be shown for full credit.  The answer alone is only worth 1 point.    Determine the freezing point of a solution that contains 78.8 g of naphthalene (C10H8, molar mass = 128.16 g/mol) dissolved in 722 mL of benzene (d = 0.877 g/mL).  Pure benzene has a melting point of 5.50°C and a freezing point depression constant of 4.90°C/m.

Prior to puberty, oocytes are dormant and protected by this follicle:

The height above the ground of a stone thrown upwards is given by s(t), where t is measured in seconds. After 1 second the height of the stone is 48 feet above the ground, and after 1.5 seconds the height of the stone is 60 feet above the ground. Find the average velocity of the stone over the time interval [1,1.5]