Author: Anonymous

Which of the following subatomic particles is/are located outside the nucleus of an atom?

Write the formula (and charge) for each ion in the order they are given. Be sure to number your answers.Write the formula for each compound.trinitrogen pentachloridesilver nitriteiron (II) bromideoxalic acid NOTE: Chemical formulas typed without proper formatting (“H2O”) will be marked incorrect.NOTE: To insert a subscript use the down “

For the ion 65Zn2+, determine the following.Number of protons: [response_blankA]Number of neutrons: [response_blankB]Number of electrons: [response_blankC]

For the ion 59Co3+, determine the following.Number of protons: [response_blankA]Number of neutrons: [response_blankB]Number of electrons: [response_blankC]

First draw the best Lewis structure for CH2O. Then answer the following questions about your structure.What is the central atom in the structure? [response_blankA]How many lone pair electron groups are on the central atom in its Lewis structure? [response_blankB]How many single bonds are in its Lewis structure? [response_blankC]How many double bonds are in its Lewis structure? [response_blankD]How many triple bonds are in its Lewis structure? [response_blankE]

For the ion 55Cr2+, determine the following.Number of protons: [response_blankA]Number of neutrons: [response_blankB]Number of electrons: [response_blankC]

Convert 9,542 m to km.[response_blankA]   NOTE: If an answer needs to be written in scientific notation, use the following format: 1.2×103 should be written as 1.2e3 or 1.2×10^31.2×10-3 should be written as 1.2e-3 or 1.2×10^-3

What is the correct name for S3O5?

Which number correctly shows 7480 in scientific notation?

21.0 g P4 reacts with excess Ni according to the reaction below. How many grams of NiP3 form?4 Ni + 3 P4 → 4 NiP3Molar masses: Ni = 58.6934 g/mol, P4 = 123.8950 g/mol, NiP3 = 151.6147 g/mol[response_blankA] NOTE: If an answer needs to be written in scientific notation, use the following format: 1.2×103 should be written as 1.2e3 or 1.2×10^31.2×10-3 should be written as 1.2e-3 or 1.2×10^-3