Author: Anonymous

If L/B > [BLANK-1], the foundation is considered continuous….

If L/B > [BLANK-1], the foundation is considered continuous. Settlement in cohesive soils is calculated using [BLANK-2] theory. Bearing capacity factors N c , N q , and N γ depend on the soil’s [BLANK-3]. Mat foundations seldom fail due to [BLANK-4] but almost always due to [BLANK-5] issues. (chose from settlement and bearing capacity to fill each blank of this statement)

7. Which of the following statements regarding the physical…

7. Which of the following statements regarding the physical examination of a patient with a behavioral problem is correct?A) It is only appropriate to perform a physical examination on a patient with a behavioral problem if he or she is unconscious or is being physically restrained.B) Although the physical exam can be difficult, the patient’s emotional state may be determined by noting facial expressions, pulse rate, and respirations.C) The physical examination of a patient with a behavioral problem often yields crucial information and should always be performed, even if the patient is violent. D) Performing a physical examination on a patient with a behavioral problem will likely cause him or her to become violent and should be avoided in the field. 

A spread footing, 10 ft x 10 ft in size is designed to suppo…

A spread footing, 10 ft x 10 ft in size is designed to support a column load of 380 kips. It will be built at grade (i.e., at the ground surface, duly leveled and compacted) at a site underlain by granular soil with total unit weight of 116 pcf and friction angle of 33 degrees. The water table is at the ground surface. What is the bearing capacity of the soil? What is the factor of safety? Shallow foundations typically require a minimum FS of 3. Is the calculated FS adequate? Solve using the following calculation steps and selecting your answer for each step by filling in its blank space using the correct value from the options provided for each. Applicable unit weight = [BLANK-1] pcf. (choices: 116 or 53.6 or 62.4) Bearing factor, N c = [BLANK-2]. (choices: 26.1 or 38.6 or 35.2) Bearing factor, N q = [BLANK-3]. (choices: 26.1 or 38.6 or 35.2) Bearing factor, N γ = [BLANK-4]. (choices: 26.1 or 38.6 or 35.2) Shape factor, s c = [BLANK-5]. (choices: 1.68 or 0.6 or 1.65) Shape factor, s q = [BLANK-6]. (choices: 1.68 or 0.6 or 1.65) Shape factor, s γ = [BLANK-7]. (choices: 1.68 or 0.6 or 1.65) Bearing capacity, q = [BLANK-8] psf. (choices: 5660 or 3962 or 3800) Original design load = [BLANK-9] lbs. (choices: 380000 or 640000 or 116000) Applied stress at the foundation level due to the column load = [BLANK-10] psf. (choices: 3800 or 6400 or 1160) Factor of Safety, FS (rounded value) = [BLANK-11]. (choices: 1.5 or 3.5 or 4.5) Is the FS adequate? [BLANK-12]. (choices: yes or no or barely)

Stark transfers land (FMV = $200,000, basis = $120,000 to th…

Stark transfers land (FMV = $200,000, basis = $120,000 to the OKT Partnership, in which she is a 1/3 partner.  Twenty months later the partnership distributes property (FMV = $150,000, basis = $50,000) to Stark, and her basis in her partnership interest immediately before the distribution (and before the addition of any gain under Section 737) is $120,000.  Assume that at the time of the contribution the distribution was not assured in any way.  How would these transactions be taxed?

The equal MSU Partnership has the following balance sheet:…

The equal MSU Partnership has the following balance sheet:     Basis FMV Property 1 $10,000 $10,000 Property 2 $4,000 $6,000 Property 3 $13,000 $10,000 Property 4 $3,000 $13,000     $30,000 $39,000         Capital, M   $10,000 $13,000 Capital, S   $10,000 $13,000 Capital, U   $10,000 $13,000     $30,000 $39,000 Partner M sells his interest to T for $13,000 when the partnership has a Code Section 754 election in effect. All four properties are capital assets. What is the basis adjustment for each asset?