Exаmple: Given f(x)=-3x2+12x-5{"versiоn":"1.1","mаth":"f(x)=-3x2+12x-5"},а) Write the functiоn in vertex fоrm:f(x)=a(x-h)2+k{"version":"1.1","math":"f(x)=a(x-h)2+k"}. b) Identify the vertex. c) Determine the axis of symmetry.Solution:a) f(x)=-3x2+12x-5 =-3(x2-4x+4-4)-5 =-3(x2-4x+4)+(-3)(-4)-5 =-3(x-2)2+12-5 =-3(x-2)2+7{"version":"1.1","math":"f(x)=-3x2+12x-5 =-3(x2-4x+4-4)-5 =-3(x2-4x+4)+(-3)(-4)-5 =-3(x-2)2+12-5 =-3(x-2)2+7"} b) The vertex is (2,7){"version":"1.1","math":"(2,7)"} c) The axis of symmetry is x=2{"version":"1.1","math":"x=2"} Exercise: Given f(x)=2x2+12x+5{"version":"1.1","math":"f(x)=2x2+12x+5"},a) Write the function in vertex form: f(x)=a(x-h)2+k{"version":"1.1","math":"f(x)=a(x-h)2+k"}. b) Identify the vertex. c) Determine the axis of symmetry.Show your work in the box below using the Graphical Equation Editor.
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