In which state has offshore gambling gained popularity? 

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In which stаte hаs оffshоre gаmbling gained pоpularity? 

Cоmputing cоmplexity аnаlysis. (1) Pleаse analyze the cоmputing complexity of the following method. Hint: Similar to mergesort, denote the complexity of the method when data array size is n as T(n). Set up a relationship between the recursive calls like T(n) = 2 T(n/2)+f(n). If f(n) = O(n), the resulted complexity is T(n) = O(nlog n). If the f(n) = O(1) , then T(n) = O(n). /**     * Recursive Helper: Uses Divide and Conquer to find the maximum sensor value      * in the range [left, right].     */    public static int findMaxDivideAndConquer(int[] readouts, int left, int right) {        // Base Case 1: Range contains a single element        if (left == right) {            return readouts[left];        }        // Divide: Split the range into two equal halves        int mid = left + (right - left) / 2;        // Conquer: Recursively solve both subproblems        int leftMax = findMaxDivideAndConquer(readouts, left, mid);        int rightMax = findMaxDivideAndConquer(readouts, mid + 1, right);        // Combine: Return the larger of the two maxes        return Math.max(leftMax, rightMax);    }       (2) Analyze the overall computing complexity of the following method (combine the knowledge in part (1)).     /**     * Main Pipeline: Analyzes peak values across exponentially shrinking windows.     */    public static int analyzeMultiScalePeaks(int[] readouts) {        int peakSum = 0;        int currentLimit = readouts.length - 1; // Upper bound index        // Outer loop halves the active window size on each pass        while (currentLimit >= 0) {                        // Perform recursive divide-and-conquer search on current range            peakSum += findMaxDivideAndConquer(readouts, 0, currentLimit);           // Shrink window size by one           currentLimit--;        }        return peakSum;    }