Type the tоpic sentence frоm bоdy pаrаgrаph 1.
Cоnsider eаch оf the E. cоli strаins listed in the tаble below. Finish filling in the table to indicate the amount of functional β-galactosidase enzyme expected to be made for each genotype under the 3 different conditions: glucose + no lactose, lactose + no glucose, both lactose and glucose. The first row, with a fully wildtype operon, is filled out for you. Remember there is both activation and repression for this operon, and they work together to modulate operon expression. Here is the logic to follow for the levels of enzyme expected to be present: Activation + no repression = High Activation + repression (or no activation + no repression) = Low No activation + repression = None Assume that more operon transcript means that more β-galactosidase enzyme is made. The genotype in the last row is a partial diploid. LacI = gene for repressor Cap = CAP-cAMP binding site next to promoter P = lac operon promoter O = Operator lacZ = gene that encodes beta-galactosidase + = Wildtype -- = Mutated c = constitutive Genotype of Cells Amount of beta-galactosidase expected (None, Low, or High) Glucose present but no lactose in the environment Lactose present but no glucose in the environment Both lactose and glucose present in the environment lacI+, Cap+ P+ O+ lacZ+ None High Low LacI--, Cap-- P+ O+ lacZ+ [answer1] [answer2] [answer3] lacI+, Cap+ P-- O+ lacZ+ [answer4] [answer5] [answer6] lacI+, Cap-- P+ Oc lacZ+/ F’ lacI--, Cap+ P+ O+ lacZ+ [answer10] [answer11] [answer12]