The results оbtаined by twо аnаlysts fоr the phosphorus content of water samples (in mM) are as follows: Analyst 1: 49.49, 49.52, 49.44, 49.58, 49.42, 49.48 Analyst 2: 49.02, 49.11, 49.45, 49.13, 49.79, 49.57 Open an Excel or on your computer or use your lab as a template in the new Tab and use the appropriate test to report (remember that you do not need to look for the exact answers, just choose the ones that are closest to the answer you received) a) The mean values of the two sets of data in mm. Analyst 1 [mean1] Analyst 2 [mean2] b) the standard deviations (for the sample) of the two sets of data in mM, Analyst 1 [deviation1] Analyst 2 [deviation2] c) the T-Confidence range of the two sets of data in mM, Analyst 1 [range1] Analyst 2 [range2] d) the percent errors if the accepted value is 49. 15mM, in % Analyst 1 [error1] Analyst 2 [error2] e) which analyst has the best precision (write Analyst 1 or Analyst 2) [precision] f) which analyst has the best accuracy (write Analyst 1 or Analyst 2) [accuracy] g) which analyst has mostly systematic error(write Analyst 1 or Analyst 2) [systematic] h) which analyst has mostly random error (write Analyst 1 or Analyst 2) [random]